A Purse Contains 6.70 Pesos In 10 Centavo And 25 Centavo Coins. If The Number Of 25 Centavo Coins Exceeds The Number Of 10 Centavo Coins By 3, How Man

A purse contains 6.70 pesos in 10 centavo and 25 centavo coins. If the number of 25 centavo coins exceeds the number of 10 centavo coins by 3, how many coins of each type are there?

Answer:

The purse contains 17 ten centavo coins and 20 twenty-five centavo coins.

Computation:

Representation

Number\:of\:25\:centavo\:coins\:(0.25)\to \boxed{x+3}\\\\Number\:of\:10\:centavo\:coins\:(0.10)\to \boxed{x}

Solving for the number of 10 centavo coins.

0.25(x+3)+0.10x=6.70\\0.25x+0.75+0.10x=6.70\\0.35x=6.70-0.75\\0.35x=5.95\\x=5.95/0.35=\boxed{17}

Solving for the number of 25 centavo coins.

x+3=17+3=\boxed{20}


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